(2a)=3*2a^2-4*2a

Solution for (2a)=3*2a^2-4*2a equation:

(2a)=3*2a^2-4*2a

We move all terms to the left:

(2a)-(3*2a^2-4*2a)=0

We get rid of parentheses

2a-3*2a^2+4*2a=0

Wy multiply elements

-6a^2+2a+8a=0

We add all the numbers together, and all the variables

-6a^2+10a=0

a = -6; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-6)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-6}=\frac{-20}{-12}
=1+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-6}=\frac{0}{-12}
=0
$